5sin^2x-7x+1=0

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Solution for 5sin^2x-7x+1=0 equation:


Simplifying
5sin2x + -7x + 1 = 0

Reorder the terms:
1 + 5in2sx + -7x = 0

Solving
1 + 5in2sx + -7x = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 5in2sx + -1 + -7x = 0 + -1

Reorder the terms:
1 + -1 + 5in2sx + -7x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 5in2sx + -7x = 0 + -1
5in2sx + -7x = 0 + -1

Combine like terms: 0 + -1 = -1
5in2sx + -7x = -1

Add '7x' to each side of the equation.
5in2sx + -7x + 7x = -1 + 7x

Combine like terms: -7x + 7x = 0
5in2sx + 0 = -1 + 7x
5in2sx = -1 + 7x

Divide each side by '5n2sx'.
i = -0.2n-2s-1x-1 + 1.4n-2s-1

Simplifying
i = -0.2n-2s-1x-1 + 1.4n-2s-1

Reorder the terms:
i = 1.4n-2s-1 + -0.2n-2s-1x-1

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